Construction Math Free Test

Take the total time allowed, 40 hours, and subtract the time already used, 9+6.5 + 8 + 10.5 = 34, to find the leftover time, 40 - 34 = 6.

1. Find the excavation depth. It is the difference in site readings .85.
25' - 83.75' = 1.5'
2. Use the formula:
Excavation Depth (difference between the site readings) x Soil Slope
1.5 x 1.5 = 2.25'

To calculate inches, divide 18 cm by 2.54 cm/in; 18 cm/2.54 = 7.0866 inches. Rounding to the tenths place, 7.0866 = 7.1 inches.

$5.50 per 8’ length x 2 (8’ lengths) x 2 kitchen counters = $22. Using the plywood would be more expensive.

The first step is to figure out how many hours the representative worked. 9:00 a.m. to 5:00 p.m. is 8 hours. In order to find the
average number of calls per hour, divide the total number of calls, 104, by the number of hours worked, 8 hours; 10% = 13 calls/hr.

To solve I = E/R for E, multiply both sides of the equation by R. The Rs cancel each other out on the right side of the equation,
so the equation becomes IR = E. The equation can be flipped ’ around to become E = IR, which is Answer A..

1. Convert feet to inches. Multiply 18' x 12" = 216"
2. Divide by 12" o.c.
216" / 12 = 18
3. Add 1 (for the end)
18 + 1 = 19

There are 14 stairs with a ratio of 3:7. The total depth is 210 in, 14 * 15 = 210 and using a simple proportion will help find the height. 3/7 = x/10;
7x = 3(210); (7x)/7 = 630/7;x= 90.
90 inches is the same as 7.5 ft, 9°/iz = 7.5.

Add up the various stages in order to figure out the total amount of time he must spend per tree;
20 min +120 min +40 min = 180 min or 3 hrs. It takes him 3 hours per tree and he has 6 trees to trim;
6 treesx 3 hrs/tree = 18 hrs total. He has 2 days to accomplish 18 hrs of work; 18 hrs/2 days = 9 hrs/day.

Multiply the total bill, t, by the decimal equivalent of 15%, 0.15. This expression is 0.151

With both pipes working, the pool is being filled at a rate of 11 gallons per minute, 5 gallons/minute + 6 gallons/minute = 11
gallons/minute. Now, divide the total amount of gallons in the pool, 6,000, by the rate, 11 gallons/minute;
6,000 + 11 =545.45.

Replace w with 14 since the package weighs 14 ounces over 2 pounds. The formula is then $C = $2.95+$0.30 x 14. The order of operations states that multiplication is always done before addition. Multiply $0.30 by 14; $0.30 x 14 = $4.20, then add the result to $2.95; $2.95+$4.20 = $7.15.

For multiple items, take the cost per item and multiply it by the number of items purchased, $135x 6 = $810.

Divide the size of the walkway, 50 cubic feet, by the amount that each bag makes, 15 cubic feet; 50/15 =3.3. A little over 3 bags are needed to fill the walkway. Therefore, 4 bags need to be purchased.

A circle will provide the largest area. In order to find the area of the circle, you must find the radius using the circumference
(perimeter), which is 12.73 ft,
C = 3.14x2xr,80 = 3.14x2xr;
r = 12.
73. The area of a circle is calculated by A=3.14r(2), giving a total of 509.8 sq. ft. If a square shape were built, the sides would be 20 x 20 (8% = 20) giving an area of only 400 sq. ft., 20 x 20 = 400. Playing around with numbers for a rectangle will show that the area would not be able to exceed the circle.